Question

Which of the following has the largest number of atoms?
A.1g Au(s)
B.1g Na(s)
C. 1g Li (s)
D. 1g Cl2(g)

Answer 1

Answer:

(i) 1 g Au = 1/197 mol = 1/197×6.022×1023 atoms

(ii) 1 g Na = 1/23 mol = 1/23×6.022×1023 atoms

(iii) 1 g Li = 1/7 mol = 1/7×6.022×1023 atoms

(iv) 1 g Cl2 = 1/71 mol = 1/71×6.022×1023 atoms

Thus, 1 g of Li has the largest number of atoms