Question

Which of the following has the maximum number of unpaired electron mg2+ or ti3+ or v3+ or fe2+

Answer 1

Answer:

Explanation:

electronic configuration of magnesium +2 = 1s^2 2s^2 2p^6 3s^0 .all orbital is completely filled , so unpaired electron is 0.

electronic configuration of Titanium 3+:- 1s22s22p63s23p63d¹4s^0

so, we conclude that 3d orbital have 1 and other orbital is filled completely , so no of unpaired electron is 1.

electronic configuration of fe2+ :-1s2 2s2 2p6 3s2 3p6 3d6 4s0 so conclude that having no unpaired electron because no any orbital is empty .

electronic configuration of Mn2+ :-1s22s22p63s23p63d 54s0.  here 3d orbital contain only five electron ,but they must have 10 electrons , so 5 electron is unpaired

so its Mn2

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Answer 2

Answer:

Fe2+

Explanation:

Mg2+ : 1s2 2s2 2p6 : no unpaired electron

Ti3+ : 1s2 2s2 2p6 3s2 3p6 3d1 : one unpaired electron

V3+ : 1s2 2s2 2p6 3s2 3p6 3d1 : two unpaired electrons

Fe2+ : 1s2 2s2 2p6 3s2 3p6 3d1 : four unpaired electrons

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