Question

which of the following has the smallest radius? N3+,N0,N3-​

Answer 1

Answer:

ve sign means more of electrons and +ve sign means lack of electrons.

Here N3- with atomic no. 7 has 7+3= 10 electrons

O2- witha tomic no. 8 has 8+2 = 10 electrons

F- with atomic no. 9 has 9+1= 10 electrons

Na+ with atomcatomic no. 11 has 9-1= 10 electrons

Mg2+with atomcatomic no. 12 has 12-2= 10 electrons

Al3+with atomcatomic no. 13 has 13-3= 10 electrons

Since all these ions have 10 electrons in their shell therefore these are isoelectronic speicies

The more + the charge, the smaller the ionic radius. Remember that - means adding electrons. These electrons go in the outermost shells. Also, when an atom loses electrons, it clings ever more tightly to the ones it has left, further reducing the ionic radius. therefore the order of ionic radii will be →

AL3+ Mg2+ Na+ F- O2- N3- (increasing order)

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Answer 2

Explanation:

Yours answer is N³+...

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