Question

Which of the following has x-1 as a factor

Answer 1

Answer:

x³+x²+x+1

x³+x²+x+1

x³+x²+x+1 Let p(x)= x³+x²+x+1

x³+x²+x+1 Let p(x)= x³+x²+x+1

x³+x²+x+1 Let p(x)= x³+x²+x+1

x³+x²+x+1 Let p(x)= x³+x²+x+1 The zero of x+1 is -1.

x³+x²+x+1 Let p(x)= x³+x²+x+1 The zero of x+1 is -1.

x³+x²+x+1 Let p(x)= x³+x²+x+1 The zero of x+1 is -1. On putting x= -1

x³+x²+x+1 Let p(x)= x³+x²+x+1 The zero of x+1 is -1. On putting x= -1p(−1)=(−1)³+(−1)²+(−1)+1

x³+x²+x+1 Let p(x)= x³+x²+x+1 The zero of x+1 is -1. On putting x= -1p(−1)=(−1)³+(−1)²+(−1)+1=−1+1−1+1=0

x³+x²+x+1 Let p(x)= x³+x²+x+1 The zero of x+1 is -1. On putting x= -1p(−1)=(−1)³+(−1)²+(−1)+1=−1+1−1+1=0Hence, by factor theorem, x+1 is a factor of x³+x²+x+1.

by BRAINLY

Answer 2

Answer:

Step-by-step explanation: