Question

Which of the following have identical bond order?
(i) CN–
(ii) NO+
(iii) O2–
(iv) O22–


NCERT Class XI
Chemistry - Exemplar Problems

Chapter 4. Chemical bonding and molecular structure

Answer 1

These could be two answer of this question...these are:_

option.....(1) & (2)

Answer 2

Both $CN^-$ and $NO^+$ have identical bond orders as they have the same number of electrons i.e 14.

Option (i) and (ii).

Explanation:

• The idea of bond order has been introduced by Linus Pauling.

• Bond order gives an idea about the 'number of electrons' involved in a 'bond in a molecule'.

• In order to calculate the bond order, we need to know the electrons in the bonding molecule and know the electrons in the antibonding molecule.

• Now we need to subtract the latter from the first and divide it by 2.

• If higher the bond order of the molecule, the higher the stability.

• $CN^-$ and $NO^+$ have the 'same bond number'.

• The 'number of electrons' in $CN^-$ is (6+7+1=14).

• The $NO^+$  'number of electrons' in ( 7+8-1=14).

Learn more about bond order

What is meant by the term bond order? Calculate the bond order of: N2, O2, O2(+) and O2(–).

https://brainly.in/question/2043851

Define bond order and give the relationship between bond order and bond length

https://brainly.in/question/5229305