Question

Which of the following have maximum number of molecules?
A. 7gN2
B. 2gH2
C. 8gO2
D. 20gNO2

Answer 1

Answer:

option (d)20gNO²............xd

Answer 2

Option B- 2g $H_2$ have maximum number of molecules.

Explanation:

• To find the compounds with maximum number of molecules, the number of molecules present in each compounds must be calculated.
• To calculate the number of molecules, the following formula must be used:

Number of molecules = $\frac{Given mass}{Molar mass}\times 6.022\times 10^{23}$

A. 7g $N_2$

Number of molecules = $\frac{Given mass}{Molar mass}\times 6.022\times 10^{23}$

Number of molecules = $\frac{7}{14}\times 6.022\times 10^{23}$

Number of molecules = 0.5 × $6.022\times 10^{23}$

Number of molecules = $3.011\times 10^{23}$

B. 2g $H_2$

Number of molecules = $\frac{Given mass}{Molar mass}\times 6.022\times 10^{23}$

Number of molecules = $\frac{2}{2.015}\times 6.022\times 10^{23}$

Number of molecules = 0.99 × $6.022\times 10^{23}$

Number of molecules = $5.977\times 10^{23}$

C. 8g $O_2$

Number of molecules = $\frac{Given mass}{Molar mass}\times 6.022\times 10^{23}$

Number of molecules = $\frac{8}{32}\times 6.022\times 10^{23}$

Number of molecules = 0.25 × $6.022\times 10^{23}$

Number of molecules = $1.505\times 10^{23}$

D. 20g $NO_2$

Number of molecules = $\frac{Given mass}{Molar mass}\times 6.022\times 10^{23}$

Number of molecules = $\frac{20}{46}\times 6.022\times 10^{23}$

Number of molecules = 0.43 × $6.022\times 10^{23}$

Number of molecules = $2.61\times 10^{23}$

From the above calculation the following data is obtained:

A. 7g $N_2$ contains $3.011\times 10^{23}$ molecules.

B. 2g $H_2$ contains $5.977\times 10^{23}$ molecules.

C. 8g $O_2$ contains $1.505\times 10^{23}$ molecules.

D. 20g $NO_2$ contains $2.61\times 10^{23}$ molecules.

• From the above values it can be inferred that option B-2g of $H_2$ have maximum number of molecules.

Learn more about such concept

Calculate number of molecules in 5.5g of CO2

(ATOMIC MASS :- C=12,O=16)

https://brainly.in/question/2882081

Calculate the number of molecules present in a drop of chloroform weighing 0.0239 ( C =12 u , H = 1u , chloroform = 35.5 u)

https://brainly.in/question/3776230

• From the above calculation it can be inferred option D- 2g $H_2$ has maximum number of molecules.