Chemistry, asked by asiskaurasis3292, 11 months ago

Which of the following have same number of atoms?
A) 16g of O2 (g) and 4g of H2 (g)
B) 16g of O2 and 44g of CO2
C)28g of N2 and 32g of O2
D) 12g of C (s) and 23g of Na (s)

Answers

Answered by stew123
29

A) Moles of O2 = Given mass/Molar mass = 16/32 = 0.5 mol

No. of atoms = 6.02 x 10^23

Moles of H2 = 4/2 = 2 mol

No. of atoms = 4 x 6.02 x 10^23 = 24.08 x 10^23

B) Moles of O2 = Given mass/Molar mass = 16/32 = 0.5 mol

No. of atoms = 6.02 x 10^23

Moles of CO2 = 44/44 = 1 mol

No. of atoms = 3 x 6.02 x 10^23 = 18.06 x 10^23

C) Moles of N2 = 28/28 = 1 mol

No. of atoms = 2 x 6.02 x 10^23 = 12.04 x 10^23

Moles of O2 = 32/32 = 1 mol

No. of atoms = 2 x 6.02 x 10^23 = 12.04 x 10^23

D) Moles of C = 12/12 = 1 mol

No. of atoms = 6.02 x 10^23

Moles of Na = 23/23 = 1 mol

No. of atoms = 6.02 x 10^23

Option C) and D) have same no .of atoms

Answered by kvrreddy1999
14

Answer:

Explanation:

A)16g of O2=16/32=0.5

4g of H2=4/2=2

0.5 is not equal to 2

B)16g of O2=0.5 as calculate above

44g of CO2=44/44=1

2is not equal to one

C)28g of N2=28/28=1

32g of O2=32/32=1

I is equal to one so C is one amongst the answers.

D)12g of C=12/12=1

23g of Na=23/23=1

1 is equal to one so D is also the answer.

Option C and D are the answers

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