Question

which of the following is a common difference of an arithmetic sequence whose =1 =7

Answer 1

Answer:

given sequence is,

1.0,1.7,2.2,3.1,...…

first term of this A.P is  a1=1.0

second term of this A.P is  a2=1.7

third term of this A.P is  a3=2.4

fourth term of this A.P is  a4=3.1

the condition for an sequence to be an A.P is their must be a common difference (i.e.,d=an+1−an)

putting n=1 in above equation

d=a2−a1=1.7−1.0=0.7

putting n=2 in above equation

d=a3−a2=2.4−1.7=0.7

putting n=3 in above equation

d=a4−a3=3.1−2.4=0.7

as we can see we get a  common difference d=0.7 for this sequence

hence this sequence forms  an A.P

with first term a1=1.0 and

common difference d=0.7

Step-by-step explanation:

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