Question

Which of the following is a point on common chord of the circles x² + y² + 2x-3y-8= 0 and x² + y² + x-8y-13=0?

pls help with valid answers asap!
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Answer 1

Answer:

The equation of the common chord of the given circles is given by (x

2

+y

2

+2x−3y+6)−(x

2

+y

2

+x−8y−13)=0

i.e. x+5y+19=0

Out of the four options, the point satisfying the above equation is (1,−4)