Question

Which of the following is a polynomial in x:
. x+1/x
b. x² + x
c. x + √2x² + 1
d. √3x + 1​

Answer 1

B is correct...

Thank you✌️❤️

Answer 2

Answer:

Polynomial in x are-

b)  x² + x

c) x + $\sqrt{2}$x² + 1

d) $\sqrt{3}$ x + 1

Step-by-step explanation:

Concept : For any expression to be an polynomial in x, the exponent of the variable x, must be a whole number (0, 1, 2, 3, 4,....)

a) x+1/x

   x + $\frac{1}{x}$ can also be written as x + $x^{-1}$.

Here the exponent of the term ($x^{-1}$) is -1. -1 is not a whole number. Thus, x + 1/x is not a polynomial in x.

b)  x² + x

Here, the exponent of the first term (x²) is 2 and the exponent of the next term ($x^{1}$) is 1. 2 and 1 are whole numbers. Thus, x² + x  is a polynomial in x.

c) x + $\sqrt{2}$x² + 1

The exponent of the first term (x) is 1. The exponent of x in second term

( $\sqrt{2}$x² ) is 2. The exponent of x in third term (1 or 1$x^{0}$) IS 0. 0, 1 and 2 are whole numbers. Thus, x + $\sqrt{2}$x² + 1 is a polynomial in x.

d) $\sqrt{3}$ x + 1

The exponent of x in the term (  $\sqrt{3}$ x) is 1. The exponent of x in the second term (1 or 1$x^{0}$) is 0. 0 and 1 are whole numbers. Thus, $\sqrt{3}$ x + 1 is a polynomial in x.

Polynomial in x are-

b)  x² + x

c) x + $\sqrt{2}$x² + 1

d) $\sqrt{3}$ x + 1

#SPJ3