Question

which of the following is a quadratic equation [x-3][x-4] =[5-x] [6-3x]

Answer 1

Answer:

hello friend here ur answer

Step-by-step explanation:

[x-3][x-4] = [5-x][6-3x]

x[x-4]-3[x-4]=5[6-3x]-x[6-3x]

x^2-4x-3x+12=30-15x-6x+3x^2

x^2-7x+12. = 3x^2-21x+3o

3x^2-x^2-21x+7x+30-12=0

2x^2-14x+28=o

take common 2 on both sides

x^2-7x+14=0

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Answer 2

ANSWER =⟩

(x-3)(x-4) = (5-x)(6-3x)

x²-4x-3x+12 = 30-15x-6x+3x²

x²-7x+12 = 30-21x+3x²

3x²-x²-21x+7x+30-12 = 0

2x²-14x+18 = 0

it is in the form of ax²+bx+c=0