Question

Which of the following is a rational number (1)√9,(2)√6,(3)√8,(4)√2​

Answer 1

Answer:

utions. All Mathematics Part I Solutions Solutions for class Class 9 Math are prepared by experts and are 100% accurate.

Page No 21:

Question 1:

Classify the decimal form of the given rational numbers into terminating and non-terminating recurring type.

(i) 135 (ii) 211 (iii) 2916 (iv) 17125 (v) 116

ANSWER:

(i) 135

Since, 5=20×51

⇒ The denominator is in the form of 2m×5n, where m and n are non-negative integers.

So, the decimal form of 135 will be terminating type.

(ii) 211

Since, 11=20×50×111

⇒ The denominator is not in the form of 2m×5n, where m and n are non-negative integers.

So, the decimal form of 211 will be non-terminating recurring type.

(iii) 2916

Since, 16=24×50

⇒ The denominator is in the form of 2m×5n, where m and n are non-negative integers.

So, the decimal form of 2916 will be terminating type.

(iv) 17125

Since, 125=20×53

⇒ The denominator is in the form of 2m×5n, where m and n are non-negative integers.

So, the Step-by-step explanation:

Answer 2

Answer:

√9 is the rational number

Step-by-step explanation:

that is because if we simplify √9 we get 3 which is a rational number ..

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