Which of the following is a rational number (1)√9,(2)√6,(3)√8,(4)√2
Answers
Answer:
utions. All Mathematics Part I Solutions Solutions for class Class 9 Math are prepared by experts and are 100% accurate.
Page No 21:
Question 1:
Classify the decimal form of the given rational numbers into terminating and non-terminating recurring type.
(i) 135 (ii) 211 (iii) 2916 (iv) 17125 (v) 116
ANSWER:
(i) 135
Since, 5=20×51
⇒ The denominator is in the form of 2m×5n, where m and n are non-negative integers.
So, the decimal form of 135 will be terminating type.
(ii) 211
Since, 11=20×50×111
⇒ The denominator is not in the form of 2m×5n, where m and n are non-negative integers.
So, the decimal form of 211 will be non-terminating recurring type.
(iii) 2916
Since, 16=24×50
⇒ The denominator is in the form of 2m×5n, where m and n are non-negative integers.
So, the decimal form of 2916 will be terminating type.
(iv) 17125
Since, 125=20×53
⇒ The denominator is in the form of 2m×5n, where m and n are non-negative integers.
So, the Step-by-step explanation:
Answer:
√9 is the rational number
Step-by-step explanation:
that is because if we simplify √9 we get 3 which is a rational number ..
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