Question

Which of the following is a recombinant type of progeny obtained by Morgan while carrying out dihybrid cross?​

Answer 1

Answer:

(A)

Explanation:

It is that correct answer ( see image )

Hope it helps you...   ; )

Answer 2

Answer:

In the first cross, Morgan got 1.3% recombinant type( brown-bodied red-eyed female and yellow-bodied and white-eyed male).

In the second cross, Morgan got 37.2% recombinant type( red-eyed normal-winged female and white-eyed miniature-winged male).

Explanation:

At first (cross A) Morgan crossed yellow-bodied(y) and white-eyed(w) females with brown-bodied(y+) red-eyed(w+) male and got a recombinant brown-bodied red-eyed female and yellow-bodied and white-eyed male progeny. He found that in the F2 generation  98.7% are the parental type and 1.3% are the recombinants.

In the second (cross B) he crossed a white-eyed and miniature-winged female(wwmm) with a red-eyed(w+) normal-winged male(m+) and got a recombinant red-eyed normal-winged female and white-eyed miniature-winged male progeny. He found that in the F2 generation 62.8% are the parental type and 37.2% are the recombinants.

After the two crosses, Morgan comes to a conclusion that in the first cross the recombinant types were low(1.3%) which means the genes for white eye and yellow body were very tightly linked. But in the second cross, the recombinants type was (37.2) which means that the genes for white eye and miniature wing were loosely linked.