Which of the following is a root of the equation 2x^2-5x-3=0
1 point
x=4
x=1
x=-3
x=3
Answers
Answered by
8
HELLO FRIENDS
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To Find :- The roots of the given equation!
2x²– 5x + 3 = 0
Using middle term splitting method !
2x²– 3x - 2x + 3 = 0
x ( 2x - 3 ) - 1 ( 2x - 3 ) = 0
( 2x - 3 ) = 0 , ( x - 1 ) = 0
x = 3/2 , x = 1
Hence, 3/2 and 1 are the roots of the equation.
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hope it will be helpful to you
Answered by
1
Answer:
option b x=1
Step-by-step explanation:
Solution:
(i) √3x2 – 2x + 3/5 = 0
Yes, the given equation is a quadratic equation since it has power of 2.
(ii) (2x + 1) (3x – 2) = 6(x + 1) (x – 2)
Let us solve the given expression,
6x2 – 4x + 3x – 2 = 6(x2 – 2x + x – 2)
6x2 – x – 2 = 6x2 – 12x + 6x – 12
12x – 6x – x = -12 + 2
5x = -10
∴ The given expression is not a quadratic equation.
(iii) (x – 3)3 + 5 = x3 + 7x2 – 1
Let us solve the given expression,
x3 – 3x2 (3) + 3x (9) – 27 + 5 = x3 + 7x2 – 1
-9x2 + 27x – 22 – 7x2 + 1 = 0
-16x2 + 27x – 21 = 0
16x2 – 27x + 21 = 0
∴ The given expression is a quadratic equation.
(iv) x – 3/x = 2, x ≠ 0
Let us solve the given expression,
x2 – 3 = 2x
x2 – 2x – 3 = 0
∴ The given expression is a quadratic equation.
(v) x + 2/x = x2, x ≠ 0
Let us solve the given expression,
By taking LCM we,
x2 + 2 = x3
x3 – x2 – 2 = 0
∴ The given expression is a quadratic equation.
(vi) x2 + 1/x2 = 3, x ≠ 0
Let us solve the given expression,
By taking LCM we,
x4 + 1 = 3x2
x4 – 3x2 + 1 = 0
∴ The given expression is not a quadratic equation.
hope it helps
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