Question

Which of the following is a solution of the equation 2X+4=3Y-1.Explain with steps
A) (-2,-3)
B) (-2,3)
(C) (2,3)
D) (2,-3)
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Answer 1

Answer:

$C)$ $(2,3)$

Step-by-step explanation:

The Given Equation is

$2x + 4 = 3y - 1$

⇒ $2x - 3y + 5 = 0$

Since we are provided with options we can substitute the values given in the options in the equation. If $L.H.S = R.H.S$ the substituted value is the solution for the equation.

$A)$  $(-2,-3)$

⇒ $2(-2) - 3(-3) + 5 = 0$

⇒ $-4 + 9 + 5 = 0$

⇒ $5 + 5 = 0$

⇒ $10 \neq 0$

⇒ $L.H.S \neq R.H.S$

∴$A)$ is not a solution for the equation

$B)$ $(-2,3)$

⇒ $2(-2) -3(3) + 5 = 0$

⇒ $-4 -9 + 5 = 0$

⇒ $-8 \neq 0$

⇒ $L.H.S \neq R.H.S$

∴$B)$ is not a solution for the equation

$C)$ $(2,3)$

⇒ $2(2) -3(3)+5=0$

⇒ $4 -9+5=0$

⇒ $0 = 0$

 ⇒ $L.H.S = R.H.S$

∴$C)$ $(2,3)$ is the solution for the equation.