Which of the following is arranged in decreasing order of size? (A) Mg2+ > A13+ > 02- (B) 02- > Mg2+ > A13+ (C) A13+ > Mg2+ > 02- (D) AB+ > 02- > Mg2+
Answers
Explanation:
Explanation:
(a) Atomic number of nitrogen is 7 and N^{3-}N
3−
has 10 electrons.
Atomic number of oxygen is 8 and O^{2-}O
2−
has 10 electrons.
Atomic number of fluorine is 9 and F^{-}F
−
has 10 electrons.
Atomic number of sodium is 11 and Na^{+}Na
+
has 10 electrons.
Atomic number of magnesium is 12 and Mg^{2+}Mg
2+
has 10 electrons.
Atomic number of aluminium is 13 and Al^{3+}Al
3+
has 10 electrons.
Therefore, in all the given ions it is common that all of them have 10 electrons.
(b) It is known that more is the positive charge on an ion smaller will be its ionic radii. Whereas more is the negative charge on an ion more will be its ionic radii.
Thus, order of increasing ionic radii for the given ions is as follows.
Al^{3+}Al
3+
< Mg^{2+}Mg
2+
< Na^{+}Na
+
< F^{-}F
−
< O^{2-}O
2−
< N^{3-}N
3−
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