Question

which of the following is correct?
1)2nd IE of Ne is more than 1st IE of Ne
2)2nd IE of Li is less than 2nd IE of Ne
3)metallic character increase from Tm to Sm
4)1st IE is exothermic while 2nd is endothermic ​

Answer 1

Answer:

(3) metallic characters increase from Tm to Sm.

Explanation:

I hope it is help full for.

Answer 2

3. Metallic character increase from Tm to Sm

Explanation:

• Ne is Neon in the periodic table. Neon is an inert gas and has a stable electronic configuration. Thus, it does not tend to lose electrons. But on providing energy it will lose electron. It is not easy to remove the first electron while the removal of the second electron is comparatively easier. Therefore, the first ionisation enthalpy of Neon would be more than Ionisation enthalpy of the second electron.

• Atomic size of Ne is more than that of Lithium,Li. The removal of electrons from an atom of large size is easy as compared to the removal of electrons from an atom of small size. So, the second IE of Li would be more than that of the second IE of Ne.
• Sm is samarium and its atomic number is 62 while Tm is Thulium and its atomic number is 69. Metallic character increases on moving from right to left in the periodic table.
• Ionisation enthalpy can be endothermic or exothermic depending upon the nature of the atom.

So, from the above discussion it is clear that option 3 is correct.