Question

which of the following is correct order regarding increasing size of atoms from smallest to largest
a) f<k<ge<br<rb b)f<ge<br<k<rb c)f<k<br<ge<rb d)f<br<ge<kr<b​

Answer 1

Answer:

d) F < Br < Ge < K < Rb

Explanation:

Fluorine is in group 7A and period 2 making it the smallest of the 5 atoms here. Br is also in group 7A but

is in period 4 making it larger than F, Ge is in group 4A and also in period 4 but is to the left of Br making it larger than

Br. K and Rb are both in group 1A but K is in period 4 and Rb is in period 5, making the Rb atom the largest of all the 5

atoms.