Question

which of the following is different from the other √7, √8, √9, √10​

Answer 1

$\sqrt{9}$

$\sqrt{9}$ is different from the other three numbers $\sqrt{7}$, $\sqrt{8}$ and $\sqrt{10}$.

Step-by-step explanation:

• Here, $\sqrt{7}$ is an irrational number since it is not expressible in the form $\dfrac{a}{b}$ where a, b are integers with non-zero b.

• Here, $\sqrt{8}=2\sqrt{2}$ is an irrational number since it is not expressible in the form $\dfrac{a}{b}$ where a, b are integers with non-zero b.

• Here, $\sqrt{9}=\sqrt{3^{2}}=3$ is a rational number since it is expressible in the form $\dfrac{a}{b}$ where a, b are integers with non-zero b.

• Here, $\sqrt{10}$ is an irrational number since it is not expressible in the form $\dfrac{a}{b}$ where a, b are integers with non-zero b.

So, we see that, $\sqrt{9}$ is the only rational number given and the rest are irrational. Thus $\sqrt{9}$ is different.

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