Question

Which of the following is equal to 1?
(a) 2° + 3° + 4°
(b) 2° x 3° x 40
(c) (3° -2°) x 49
(d) (3° - 20) x (3° +2°)​

Answer 1

Answer:

a ) 2⁰+3⁰+4⁰=1 because a⁰=1 ....

Answer 2

Given:

We have different equations which are

(a) 2° + 3° + 4°

(b) 2° $\times$ 3°  $\times$  40

(c) (3° -2°)  $\times$  49

(d) (3° - 20)  $\times$  (3° +2°)​

To Find:

We have to find the equation which is equal to 1?

Step-by-step explanation:

• We will simplify all the equations and find their values.

• a) We have  2° + 3° + 4°

         We know anything to the power 0 will be equal to 1 hence

          $2^\circ+3^\circ+4^\circ=1+1+1=3$

• B) we have other equation which is  2° $\times$ 3°  $\times$  40

       We will simplify it as follows as

       $2^\circ\times3^\circ\times40=1\times1\times40=40$

• c) We have the equation which is  (3° -2°)  $\times$  49

       we can silplify the equation as follows as

      $(3^\circ-2^\circ)\times49=(1-1)49=0$

• d) we have the equation which is  (3° - 20)  $\times$  (3° +2°)​

       we can simplify it as

      $(3^\circ-20)\times(3^\circ+2^\circ)=(1-20)(2)=-38$

Hence we can see that none of the above equation will result to 1.