Question

Which of the following is incorrect for XeO2F2 and PCI5?

a)Axial P-CL bonds are longer than equatorial P-CI bonds

b)Both have same hybridisation and shape

c)Both have same hybridisation and geometry

d)In XEO2F2 both oxygens and lone pair occupies in trigonal planar​

Answer 1

Explanation:

Which of the following is incorrect for XeO2F2 and PCI5?

a) Axial P-CL bonds are longer than equatorial P-CI bonds

b) Both have same hybridisation and shape ✔

c) Both have same hybridisation and geometry

d) In XEO2F2 both oxygens and lone pair occupies in trigonal planar

Explaination :-

Let's check all the options then we say that which option is incorrect.

Option 1 :-

It's correct. Axial chlorine in PCl5 have longer bond length then equatorial chlorine atoms because axial bond suffer more repulsion than equatorial bond pairs.

Option 2 :-

Let's Calculate the hybridisation of both :-

As we know that :-

• H = 1/2 × [V + M - C + A]

Here,

V = Valency of central atom

M = no. of monovalent atoms

C = charge of cation

A = charge in Anion

Then,

In XeO2F2

H = 1/2 × [8 + 2]

→ 1/2 × 10

→ 5 (sp³d)

And

In PCl5

H = 1/2 × [5 + 5]

→ 1/2 × 10

→ 5 (sp³d)

Here, we see that both have same hybridisation but Structure of PCl5 is trigonal Bipyramidal and structure of XeO2F2 is See-saw .

Hence,

Option 2 is incorrect.

Option 3 :-

Both have same hybridisation and geometry. So, This option is correct.

Option 4 :-

In XeO2F2 both oxygen and lone pairs occupies in trigonal planar.

Hence, This option is correct.