Chemistry, asked by gghotmail2494, 10 months ago

Which of the following is most basic?
(a) CH3NH2
(b) (CH3)2NH
(c) (CH3 )3N
(d) C6H5NH2

Answers

Answered by Anonymous
9

(CH₃)₂NH is most basic most basic among all others.

  • Basicity is the ability of the atom to donate its lone pair of electrons.
  • In aniline nitrogen is directly attached with the benzene ring which leads to the delocalization of lone pair of electrons of nitrogen atom in the benzene ring. This leads to the less availability of the electron for donation.
  • In case of (CH₃)₃N, lone pair of electrons did not take place in resonance. But while taking steric hindrance and inductive effect into considerations (CH₃)₂NH is more basic than (CH₃)₃N.

Increasing order of basicity is

C₆H₅NH₂ < (CH₃)₃N < CH₃NH₂ < (CH₃)₂NH

Answered by mindfulmaisel
1

\bold{\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH}} is the most basic compound.

Option: (b)

Explanation:  

  • If you consider this steric hindrance and the inductive effect of the methyl group present in the following compound we come into conclusion that \bold{\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH}} is more basic than \bold{\mathrm{CH}_{3} \mathrm{NH}_{3}}.  
  • Now in case of aniline there is high amount of steric hindrance due to the very closely placed benzene ring and the lone pair of electron which is present in nitrogen atom cannot be distributed in the benzene ring.  

Learn more about steric hindrance

Explain steric hindrance with example

https://brainly.in/question/8040054

What is steric hindrance. Explain with examples?

What is its effect on reaction mechanism?

https://brainly.in/question/13197915

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