Math, asked by karanchikane416, 6 months ago

Which of the following is not a perfect cube. *



216

1000

243

125

Answers

Answered by jayantisarkar654
1

Answer:

243

Step-by-step explanation:

because 7 cube is 343

not 243

Answered by tanmayakumarp3
0

Step-by-step explanation:

Here,

\sqrt[3]{216} = \sqrt[3]{6*6*6 }= 6

\sqrt[3]{1000} = \sqrt[3]{10*10*10} = 10

\sqrt[3]{243} =  \sqrt[3]{3*3*3*3*3} = 3 \sqrt[3]{9}

\sqrt[3]{125} = \sqrt[3]{5*5*5} = 5

Since, cube root of 243 is 3\sqrt[3]{9} which is not a perfect cube root.

Hence, 243 is not a perfect cube. (Ans)

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