Question

Which of the following is not a Pythagorean triplet?
(a) (3, 4, 5)
(b) (7, 24, 25)
(c) (11, 60, 61)
(d) (9, 41, 42)

Answer 1

(d) (9;41;42) is not a Pythagorean triplet
because it doesn't satisfy the Pythagoras theorem
(H sq.=b sq.+p sq.)
(42 sq. =41 sq.+9sq.)
(1764=1681+81)
1764=1762
above equation is not possible
so it is not Pythagorean tripet

Answer 2

✴HEY DEAR ✴


HERE IS UR ANS

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ACCORDING TO PYTHAGORAS THEOREM

${h}^{2} = {b}^{2} + {p}^{2}$
${3}^{2} + {4}^{2} = {5}^{2}$
$9 + 16 = 25$
$25 = 25$
HENCE IT SATISFY PYTHAGORAS THEOREM

${7}^{2} + {24}^{2} = {25}^{2}$
$49 + 576 = 625$
$625 = 625$
HENCE THIS ALSO SATISFY PYTHAGORAS THEOREM


${11}^{2} + {60}^{2} = {61}^{2}$
$121 + 3600 = 3721$
$3721 = 3721$
HENCE IT IS ALSO SATISFY PYTHAGORAS THEOREM


${9}^{2} + {41}^{2} = {42}^{2}$
$81 + 1681 = 1764$
$1762 = 1764$
HENCE THIS TERM DOESN'T SATISFY PYTHAGORAS THEOREM



HENCE UR ANS IS 【 D 】


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