Math, asked by ansh7663, 8 months ago

Which of the following is not a quadratic equation?
(a) 3x - 1 = x + 5
(b) (x + 2)2 = 2(x2-5)
(c)(2x + 3) = 2x2 +6
(d) (x - 1)² = 3x2 + x -2

Answers

Answered by TrickYwriTer
31

Step-by-step explanation:

To Find -

  • Which of the following is not a quadratic equation.

Let check all the options and find which is not a quadratic equation.

Option 1 :-

→ 3x - 1 = x + 5

→ 2x - 6 = 0

Option 2 :-

→ (x + 2)² = 2(x² - 5)

→ x² + 4 + 4x = 2x² - 10

→ x² - 4x - 14

Option 3 :-

→ (2x + 3) = 2x² + 6

→ 2x² - 2x + 3

Option 4 :-

→ (x - 1)² = 3x² + x - 2

→ x² - 2x + 1 = 3x² + x - 2

→ 2x² + 3x - 3

Here, we see that all options are in the form of quadratic equation except 1

Hence,

Option (1) is correct.

Additional information :-

  • Polynomial of degrees 1, 2 and 3 are called linear, quadratic and cubic polynomial.
  • A quadratic polynomial in x with real coefficients is of the form ax² + bx + c, where a, b, c are real numbers with a ≠ 0
  • A quadratic polynomial can have at most 2 zeroes and a cubic polynomial can have at most 3 zeroes.

Anonymous: Good one bro!
vinay26111976: option a
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LOVELYSOUL25: good job
Answered by silentlover45
2

\large{\boxed{\underline{\underline{\bf{\red{Answer:-}}}}}}

\implies (a) 3x - 1 = x + 5

\large\underline\mathrm{The \: correct \: options \: is \: (1) \:.}

\large\underline\mathrm{To \: find}

  • Which of the following is not a quadratic equation.

\large\underline\mathrm{Solution}

  • Let check all the options and find which is not a quadratic equation.

\large\underline\mathrm{Options \:  (a) \: :}

\implies 3x - 1 = x + 5

\implies 3x - x = 5 + 1

\implies 2x - 6 = 0

\large\underline\mathrm{Options \:  (b) \: :}

\implies (x + 2)² = 2(x² - 5)

\implies x² + 4 + 4x = 2x² - 10

\implies x² - 4x - 14 = 0

\large\underline\mathrm{Options \:  (c) \: :}

\implies 2x + 3 = 2x² + 6

\implies 2x² - 2x + 3

\large\underline\mathrm{Options \:  (d) \: :}

\implies (x - 1)² = 3x² + x - 2

\implies x² - 2x + 1 = 3x² + x - 2

\implies 2x² + 3x - 3

\large\underline\mathrm{hence,}

\large\underline\mathrm{The \: correct \: options \: is \: (a) \:.}

\large\underline\mathrm{Hope \: it \: helps \: you \: plz \: mark \: me \: brainlist}

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