Question

Which of the following is not a solution and the equation 2x + 3y = 5?
(a) x = 1; y = 1 (b) x = −2; y = 3 (c) x = 4; y = −1 (d) x = 1; y = 7​

Answer 1

Answer:

option (d)

Step-by-step explanation:

2(1)+3(1)=5

2(-2)+3(3)=5

2(4)+3(-1)=5

2(1)+3(7)=23

so option d is not a solution.

Answer 2

Answer:

The values $x = 1; y = 7$ is not the solution set of the given equation.

Step-by-step explanation:

Given the equation $2x + 3y = 5$

Using the substitution method,  place the given set of values of x and y  in the given equation and find the solution.

If the result is five, then that pair of values form the solution set of the given equation otherwise, not the solution.

Take $x = 1; y = 1$

Consider the left hand side of the equation and substitute the values of x and y, hence $2x + 3y=2\times 1+3\times 1=5$

Since the result is 5, the set of values of x and y satisfy the equation.

Similarly, doing with the other set of values:

If $x = -2; y = 3$  then $2x + 3y = 2\times (-2)+3\times 3=-4+9=5$

If $x = 4; y = -1$  then $2x + 3y = 2\times 4+3\times (-1)=8-3=5$

If $x = 1; y = 7$  then $2x + 3y = 2\times 1+3\times 7=2+21\ne5$

Therefore, the last set of values $x = 1; y = 7$ is not the solution of the given equation.

So, the correct answer is option 4.