Math, asked by mirbashirahmedd, 6 months ago

which of the following is not Arthemetic progression
-1.2,0.8,2.8
3,3+under root 2,3+under root 2,3+3under root
4/3,7/3,9/3,12/3
-1/5,-2/5,-3/5

Answers

Answered by rishikamaini0
1

Step-by-step explanation:

For Arithmetic progression the series have common difference in two consecutive terms i.e. a_2-a_1=a_3-a_2a

2

−a

1

=a

3

−a

2

(A) - 1.2, 0.8, 2.8, ...

Here, a_1=-1.2,a_2=0.8,a_3=2.8a

1

=−1.2,a

2

=0.8,a

3

=2.8

0.8-(-1.2)=2.8-0.80.8−(−1.2)=2.8−0.8

2=22=2

So, the series given is an A.P.

(B) 3,3+\frac{1}{2},3+\frac{2}{2},3+\frac{3}{2},..3,3+

2

1

,3+

2

2

,3+

2

3

,..

Here, a_1=3,a_2=3+\frac{1}{2}=\frac{7}{2},a_3=3+\frac{2}{2}=4a

1

=3,a

2

=3+

2

1

=

2

7

,a

3

=3+

2

2

=4

\frac{7}{2}-3=4-\frac{7}{2}

2

7

−3=4−

2

7

\frac{1}{2}=\frac{1}{2}

2

1

=

2

1

So, the series given is an A.P.

(C) 4,7,9,12,..

Here, a_1=4,a_2=7,a_3=9a

1

=4,a

2

=7,a

3

=9

7-4=9-77−4=9−7

3\neq 23

=2

So, the series given is not an A.P.

Therefore, option C is correct.

#Learn more

Q. Which of the following are APs? If they form an A.P. find the common difference d and write three more terms.

(i) 2, 4, 8, 16 …

(ii) 2, 5/2, 3, 7/2 ....

(iii) -1.2, -3.2, -5.2, -7.2 …

(iv) -10, - 6, - 2, 2 …

(v) 3, 3 + √2, 3 + 2√2, 3 + 3√2

(vi) 0.2, 0.22, 0.222, 0.2222 ….

(vii) 0, - 4, - 8, - 12 …

(viii) -1/2, -1/2, -1/2, -1/2 ....

(ix) 1, 3, 9, 27 …

(x) a, 2a, 3a, 4a …

(xi) a, a2, a3, a4 …

(xii) √2, √8, √18, √32 ...

(xiii) √3, √6, √9, √12 ...

(xiv) 12, 32, 52, 72 …

(xv) 12, 52, 72, 73 …

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