which of the following is one root of the quadratic equation x²-7x+10=0
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Answer:
2+7x+10=0
x=2(1)−7±(7)2−(4)(1)(10)
x=2−7±49−40
x=2−7±9
x=2−7±3
x=2−7+3 and x=2−7−3
So, the answer comes out to be, x=−2and x=−5
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Answered by
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Step-by-step explanation:
x²-7x+10=0
x²-5x-2x+10=0
x(x-5)-2(x-5)=0
(x-2)(x-5)=0
x=2
x=5
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