Question

which of the following is power of 3?
a.2345
b.9875
c.6504
d.9833; which of the following is power of 3?; a.2345; b.9875; c.6504; d.9833

Answer 1

out of the above options , only 6504 is divisible by 3 bcoz...
(a) 2345 = 2+3+4+5 =14,which is not a multiple of 3
(b) 9875 = 9+8+7+5 = 29,which ia not a multiple of 3
(c) 6504 = 6+5+0+4 = 15,which is a multiple of 3
(d) 9833 = 9+8+3+3 = 23,which is not a multiple of 3...
Thus ,only 6504 is divisible by 3,so it is the power of 3 ...

Answer 2

The given question is we have to find which of the following option is a power of 3 .

The given options are

2345,9875,6504,9833.

The condition for a number to be the power of 3 is that the number should be divided by 3 exactly without leaving the remainder.

$2345 \div 3 = 781.6 \\ 9875 \div3 = 3291.66 \\ 6504 \div 3 = 2168 \\ 9833 \div 3 = 3277.66$

Based on the above calculations.

It seems that the numbers in the option a, b and c are not exactly divided by 3. they are seems to be leave some remainders.

Hence, they cannot be a power of 3.

The option c) 6504 is divided by 3 without leaving any remainder, the quotient is a whole number.

Therefore, it is the power of 3.

Hence, the option C is correct

# spj2

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