Question

Which of the following is the correct method of preparation of methyl fluoride?
(a) $CH_4 + HF \rightarrow$
(b) $CH_3OH + HF \rightarrow$
(c) $CH_4 + F_2 \rightarrow$
(d) $CH_3Br + AgF \rightarrow$

Answer 1

d)

bcz it is the swarts method of substitution of halides

by this the electronegativity difference is very low so the reaction occur faster

Answer 2

Answer:

d) CH3Br +AgF=CH3F(Methyl Fluoride) +AgBr

Explanation:

The process is stated a the Swart's Reaction.

In Swarts reaction, alkyl fluorides are prepared by heating alkyl chlorides or bromides with salts such as silver fluoride (AgF) cobalt fluoride (CoF3)  or we can say that Swarts Reaction is a method of substitution of Halides.

This process if faster compared to others because the electronegativity difference is very low and thus the reaction occurs faster.