Biology, asked by mavigeiafederova, 23 days ago

Which of the following is the correct procedure of measuring flour? 1. Sift the flour. 2. Prepare all the needed materials 3. Level off the excess ingredients with spatula 4. Scoop to fill the measuring cup to overflow. Do not shake.

A. 1, 2, 3 and
B. 2, 1, 4 and 3
C. 4, 3, 2 and 1
D. 2, 3, 4 and 1​

Answers

Answered by MrGoodBoi
2

Answer:

Correct option is

B

3x(x−2)(x+2)

Given volume of cuboids is 3x

3

−12x

The volume of cuboid =lbh =3x(x

2

−4)

We know x

2

−y

2

=(x+y)(x−y)

∴3x(x

2

−4) =3x(x+2)(x−2)

Then dimensions are 3x,(x+2) and (x−2).

Answered by MrGoodBoi
0

Answer:

Correct option is

B

3x(x−2)(x+2)

Given volume of cuboids is 3x

3

−12x

The volume of cuboid =lbh =3x(x

2

−4)

We know x

2

−y

2

=(x+y)(x−y)

∴3x(x

2

−4) =3x(x+2)(x−2)

Then dimensions are 3x,(x+2) and (x−2).

Answered by MrGoodBoi
0

Answer:

Correct option is

B

3x(x−2)(x+2)

Given volume of cuboids is 3x

3

−12x

The volume of cuboid =lbh =3x(x

2

−4)

We know x

2

−y

2

=(x+y)(x−y)

∴3x(x

2

−4) =3x(x+2)(x−2)

Then dimensions are 3x,(x+2) and (x−2).

Answered by MrGoodBoi
0

Answer:

Correct option is

B

3x(x−2)(x+2)

Given volume of cuboids is 3x

3

−12x

The volume of cuboid =lbh =3x(x

2

−4)

We know x

2

−y

2

=(x+y)(x−y)

∴3x(x

2

−4) =3x(x+2)(x−2)

Then dimensions are 3x,(x+2) and (x−2).

Answered by MrGoodBoi
0

Answer:

Correct option is

B

3x(x−2)(x+2)

Given volume of cuboids is 3x

3

−12x

The volume of cuboid =lbh =3x(x

2

−4)

We know x

2

−y

2

=(x+y)(x−y)

∴3x(x

2

−4) =3x(x+2)(x−2)

Then dimensions are 3x,(x+2) and (x−2).

Answered by MrGoodBoi
0

Answer:

Correct option is

B

3x(x−2)(x+2)

Given volume of cuboids is 3x

3

−12x

The volume of cuboid =lbh =3x(x

2

−4)

We know x

2

−y

2

=(x+y)(x−y)

∴3x(x

2

−4) =3x(x+2)(x−2)

Then dimensions are 3x,(x+2) and (x−2).

Answered by MrGoodBoi
0

Answer:

Correct option is

B

3x(x−2)(x+2)

Given volume of cuboids is 3x

3

−12x

The volume of cuboid =lbh =3x(x

2

−4)

We know x

2

−y

2

=(x+y)(x−y)

∴3x(x

2

−4) =3x(x+2)(x−2)

Then dimensions are 3x,(x+2) and (x−2).

Answered by MrGoodBoi
0

Answer:

Correct option is

B

3x(x−2)(x+2)

Given volume of cuboids is 3x

3

−12x

The volume of cuboid =lbh =3x(x

2

−4)

We know x

2

−y

2

=(x+y)(x−y)

∴3x(x

2

−4) =3x(x+2)(x−2)

Then dimensions are 3x,(x+2) and (x−2).

Answered by MrGoodBoi
0

Answer:

Correct option is

B

3x(x−2)(x+2)

Given volume of cuboids is 3x

3

−12x

The volume of cuboid =lbh =3x(x

2

−4)

We know x

2

−y

2

=(x+y)(x−y)

∴3x(x

2

−4) =3x(x+2)(x−2)

Then dimensions are 3x,(x+2) and (x−2).

Answered by MrGoodBoi
0

Answer:

Correct option is

B

3x(x−2)(x+2)

Given volume of cuboids is 3x

3

−12x

The volume of cuboid =lbh =3x(x

2

−4)

We know x

2

−y

2

=(x+y)(x−y)

∴3x(x

2

−4) =3x(x+2)(x−2)

Then dimensions are 3x,(x+2) and (x−2).

Answered by MrGoodBoi
0

Answer:

Correct option is

B

3x(x−2)(x+2)

Given volume of cuboids is 3x

3

−12x

The volume of cuboid =lbh =3x(x

2

−4)

We know x

2

−y

2

=(x+y)(x−y)

∴3x(x

2

−4) =3x(x+2)(x−2)

Then dimensions are 3x,(x+2) and (x−2).

Answered by MrGoodBoi
0

Answer:

Correct option is

B

3x(x−2)(x+2)

Given volume of cuboids is 3x

3

−12x

The volume of cuboid =lbh =3x(x

2

−4)

We know x

2

−y

2

=(x+y)(x−y)

∴3x(x

2

−4) =3x(x+2)(x−2)

Then dimensions are 3x,(x+2) and (x−2).

Answered by MrGoodBoi
0

Answer:

Correct option is

B

3x(x−2)(x+2)

Given volume of cuboids is 3x

3

−12x

The volume of cuboid =lbh =3x(x

2

−4)

We know x

2

−y

2

=(x+y)(x−y)

∴3x(x

2

−4) =3x(x+2)(x−2)

Then dimensions are 3x,(x+2) and (x−2).

Answered by MrGoodBoi
0

Answer:

Correct option is

B

3x(x−2)(x+2)

Given volume of cuboids is 3x

3

−12x

The volume of cuboid =lbh =3x(x

2

−4)

We know x

2

−y

2

=(x+y)(x−y)

∴3x(x

2

−4) =3x(x+2)(x−2)

Then dimensions are 3x,(x+2) and (x−2).

Answered by MrGoodBoi
0

Answer:

Correct option is

B

3x(x−2)(x+2)

Given volume of cuboids is 3x

3

−12x

The volume of cuboid =lbh =3x(x

2

−4)

We know x

2

−y

2

=(x+y)(x−y)

∴3x(x

2

−4) =3x(x+2)(x−2)

Then dimensions are 3x,(x+2) and (x−2).

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