Question

Which of the following is the difference between the squares of two consecutive natural number is:
(i) sum of the two numbers
(ii) difference of the numbers
(iii) twice the sum of the two numbers
(iv) twice the difference between the two numbers.

Answer 1

Answer:

(i) sum of the 2 no.s

Explanation :

let the no.s be (a) and (a-1)

Difference between the square

= $a^{2} -(a+1)^{2}$

inserting the formula... {$a^{2} -b^{2}$ = (a+b) (a-b)}

= (a - a +1) (a + a- 1)

=  (1) (2a - 1)

= 2a-1

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Answer 2

Answer:

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Step-by-step explanation:

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