Which of the following is the equation of the line that is parallel to 2x + y = 3 and passes through the point (1, 2)?
Answers
Answered by
1
Answer:
2x−3y=1--------(i)
⇒−3y−1−2x
⇒y=
3
2x
−1
[y=mx+c]
∴m=
3
2
equation of line AB
x−x
1
y−y
1
=
x
2
−x
1
y
2
−y
1
x−1
y−3
=
1−1
−7−3
x−1
y−3
=0
⇒y−3=0
⇒y=3
From (i)
2x−3y=1
2x−3×3=1
⇒2x=10
⇒x=5
p=(x.y)=(5,3)
equation of MN at (5,3)
y−y
1
=m(x−x
1
)
y−3=
3
2
(x−5)
⇒3(y−3)=2(x−5)
⇒3y−9=2x−10
⇒3y−2x=−10+9
⇒3y−2x=−1
2x−3y−1=0
Answered by
1
Step-by-step explanation:
Correct option is
A
2x−3y+8=0
Given that,
2x−3y=1--------(i)
⇒−3y−1−2x
⇒y=
3
2x
−1
[y=mx+c]
∴m=
3
2
equation of line AB
x−x
1
y−y
1
=
x
2
−x
1
y
2
−y
1
x−1
y−3
=
1−1
−7−3
x−1
y−3
=0
⇒y−3=0
⇒y=3
From (i)
2x−3y=1
2x−3×3=1
⇒2x=10
⇒x=5
p=(x.y)=(5,3)
equation of MN at (5,3)
y−y
1
=m(x−x
1
)
y−3=
3
2
(x−5)
⇒3(y−3)=2(x−5)
⇒3y−9=2x−10
⇒3y−2x=−10+9
⇒3y−2x=−1
2x−3y−1=0
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