Question

which of the following is the root of equation x2+ 4x- 5-- 0?​

Answer 1

Answer:

x²+4x-5

x²+(5-1)x-5

x²+5x-x-5

x(x+5)-1(x+5)

(x+5) (x-1)

x+5=0

x=-5

x-1=0

x=1

Hope it helps you

Answer 2

x2 + 4x + 5 = 0. Here, a = 1, b = 4, c = 5. So, b2 – 4ac = 16 – 20 = – 4 < 0. Since the square of a real number cannot be negative, therefore √b2-4ac not have any real value