Question

which of the following is the solution set for the simultaneous equation ?(2x-1)/3=(y+6)/5=(3x-y)/7​

Answer 1

Answer:

x + 7y = 10; .....(I)

3x – 2y = 7 .....(II)

Multiplying (I) with 3

3x + 21y = 30; .....(III)

3x – 2y = 7 .....(IV)

Subtracting (IV) from (III) we get

23y = 23

⇒y = 1

Putting the value of y in (IV) we get

3x – 2 = 7

⇒3x = 7 + 2 = 9

⇒3x = 9

⇒x = 3

Thus, (x, y) = (3, 1)

please mark as brilliant answer

Answer 2

Answer:

x = 2, y = -1

Step-by-step explanation:
the system of equations (2x-1)/3=(y+6)/5=(3x-y)/7​ can be written as
 (2x-1)/3 = (3x-y)/7      ...equation 1

and (y+6)/5=(3x-y)/7​   ...equation 2

cross multiplying eq 1, we get
5x + 3y = 7

and cross multiplying eq 2, we get
15x- 12y = 42

dividing eq 2 by 3, we get
5x - 4y = 14                     ...equation 3

now from equations 1 and 3, by elimination method,

     5x + 3y = 7
     5x - 4y = 14
    -    +        -        
           7y   = -7
   therefore, y = -1

now putting y in eq 1,
  5x + 3(-1) = 7
   we get x = 2