Which of the following is true about the SI unit of universal constant due to gravity and the acceleration due to gravity:
(1 Point)
(a) both haven same SI unit
(b) universal constant does not have an SI unit
(c) acceleration due to gravity does not have an SI unit
(d) Both universal constant and acceleration due to gravity does not have an SI unit
Answers
acceleration due to gravity does not have si unit
Answer:
(c) acceleration due to gravity does not have an SI unit
Definition
According to Newton's law of universal gravitation, the attractive force (F) between two point-like bodies is directly proportional to the product of their masses (m1 and m2) and inversely proportional to the square of the distance, r, between them:
According to Newton's law of universal gravitation, the attractive force (F) between two point-like bodies is directly proportional to the product of their masses (m1 and m2) and inversely proportional to the square of the distance, r, between them:{\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}\,.}{\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}\,.}
According to Newton's law of universal gravitation, the attractive force (F) between two point-like bodies is directly proportional to the product of their masses (m1 and m2) and inversely proportional to the square of the distance, r, between them:{\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}\,.}{\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}\,.}The constant of proportionality, G, is the gravitational constant. Colloquially, the gravitational constant is also called "Big G", for disambiguation with "small g" (g), which is the local gravitational field of Earth (equivalent to the free-fall acceleration).[2][3] Where M⊕ is the mass of the Earth and r⊕ is the radius of the Earth, the two quantities are related by:
According to Newton's law of universal gravitation, the attractive force (F) between two point-like bodies is directly proportional to the product of their masses (m1 and m2) and inversely proportional to the square of the distance, r, between them:{\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}\,.}{\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}\,.}The constant of proportionality, G, is the gravitational constant. Colloquially, the gravitational constant is also called "Big G", for disambiguation with "small g" (g), which is the local gravitational field of Earth (equivalent to the free-fall acceleration).[2][3] Where M⊕ is the mass of the Earth and r⊕ is the radius of the Earth, the two quantities are related by:g =
According to Newton's law of universal gravitation, the attractive force (F) between two point-like bodies is directly proportional to the product of their masses (m1 and m2) and inversely proportional to the square of the distance, r, between them:{\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}\,.}{\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}\,.}The constant of proportionality, G, is the gravitational constant. Colloquially, the gravitational constant is also called "Big G", for disambiguation with "small g" (g), which is the local gravitational field of Earth (equivalent to the free-fall acceleration).[2][3] Where M⊕ is the mass of the Earth and r⊕ is the radius of the Earth, the two quantities are related by:g = GM⊕
According to Newton's law of universal gravitation, the attractive force (F) between two point-like bodies is directly proportional to the product of their masses (m1 and m2) and inversely proportional to the square of the distance, r, between them:{\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}\,.}{\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}\,.}The constant of proportionality, G, is the gravitational constant. Colloquially, the gravitational constant is also called "Big G", for disambiguation with "small g" (g), which is the local gravitational field of Earth (equivalent to the free-fall acceleration).[2][3] Where M⊕ is the mass of the Earth and r⊕ is the radius of the Earth, the two quantities are related by:g = GM⊕/
According to Newton's law of universal gravitation, the attractive force (F) between two point-like bodies is directly proportional to the product of their masses (m1 and m2) and inversely proportional to the square of the distance, r, between them:{\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}\,.}{\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}\,.}The constant of proportionality, G, is the gravitational constant. Colloquially, the gravitational constant is also called "Big G", for disambiguation with "small g" (g), which is the local gravitational field of Earth (equivalent to the free-fall acceleration).[2][3] Where M⊕ is the mass of the Earth and r⊕ is the radius of the Earth, the two quantities are related by:g = GM⊕/r⊕2
Explanation:
Notations for the gravitational constant
Values of G Units
6.67430(15)×10−11[1] m3⋅kg–1⋅s–2
4.30091(25)×10−3 pc⋅M⊙–1⋅(km/s)2
The gravitational constant (also known as the universal gravitational constant, the Newtonian constant of gravitation, or the Cavendish gravitational constant),[a] denoted by the letter G, is an empirical physical constant involved in the calculation of gravitational effects in Sir Isaac Newton's law of universal gravitation and in Albert Einstein's general theory of relativity.
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