Question

which of the following isoelectronic species has the smallest radius?
A) Rb+
B) Se2-
C)Br-
D) Sr+2
​

Answer 1

Answer:

Mg2+ has 12 protons and the nuclear charge is highest and thus this will be the smallest.

Explanation:

Mg2+ has 12 protons and the nuclear charge is highest and thus this will be the smallest.

Answer 2

The correct option is, (D) $Sr^{2+}$

What is isoelectronic species?

In isoelectronic species, there the number of electrons would be equal but the elements would be different. In other words, ions and atoms which are having equal numbers of electrons are called the isoelectronic species.

According to the question:

For the isoelectronic species, size of the species can be given by nuclear charge, higher the nuclear charge smaller will be the size of the ion. Out of the given isoelectronic species,$Sr^{2+}$ has the higher nuclear charge and hence, the smallest ionic radius.

Hence, the smallest ionic radius is $Sr^{2+}$.

Learn more about isoelectronic species here,

https://brainly.in/question/118329?msp_poc_exp=4

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