Question

Which of the following isomeric heptanes can yield seven different monochlorinated products upon free radical chlorination?
(a) 3-methylhexane
(b) 2,2-dimethylpentane
(c) 2-methylhexane
(d) 2,3-dimethylpentane

Answer 1

(a) 3 -Methylhexane                             (b) 2, 2-Dimethylpentane 
(c) 2-Methylhexane                              (d) 2, 3 -Dimethylpentane 
(e) 2, 4-Dimethylpentane

PLEASE MARK AS BRAINLIEST

Answer 2

Answer:

(a) 3-methylhexane

Explanation:

Heptane is the member of the alkane having the formular of C7H16.  These specifications refer to the heptane petroleum hydrocarbon fraction having a relative  proportion of isomers varying with the production lot.

Their isomers are

= ch3ch2ch2ch2ch2ch2ch3 =heptane

= ch3ch(ch3)ch2ch2ch2ch3 =2-methylhexane

= ch3c(ch3)2ch2ch2ch3 =2,2-dimethylpentane

= ch3ch2ch(ch3)ch2ch2 ch3 =3-methylhexane

= ch3ch(ch3)ch(ch3)ch2ch3 =2,3-dimethylpentane

In 3-methylhexane, none out of the seven carbon atoms are equivalent and thus it gives seven different monochlorinated products upon free radical chlorination. Thus, the equation for the same is -

7CH3 --- H3C1−C2H2−C3H7CH3|−C4H2−C5H2−C6H3