Question

Which of the following lanthanoid ions is diamagnetic ?
(At nos. Ce = 58, Sm = 62, Eu = 63, Yb = 70)
(a) Sm²⁺
(b) Eu²⁺
(c) Yb²⁺
(d) Ce²⁺

Answer 1

hi friend.....

the correct option is (c) Yb²⁺

Lanthanoid ion with no unpaired electron is diamagnetic in nature.

Ce58 = [Xe]4f² 5d0 6s²

Ce2+ = [Xe]4f² (two unpaired electrons)

Sm62 = [Xe]4f6 5d0 6s2

Sm2+=[Xe]4f6 (six unpaired electrons)

Eu63 = [Xe]4f7 5d0 6s²

Eu2+=[Xe]4f7 (seven unpaired electrons)

Yb70 = [Xe]4f¹⁴ 5d0 6s²

Yb2+=[Xe]4f¹⁴ (no unpaired electrons)

Because of the absence of unpaired

electrons, Yb²⁺ diamagnetic.

hope I answered your question...

Answer 2

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HERE IS UR ANSWER

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option C is correct