Which of the following lanthanoid ions is diamagnetic ?
(At nos. Ce = 58, Sm = 62, Eu = 63, Yb = 70)
(a) Sm²⁺
(b) Eu²⁺
(c) Yb²⁺
(d) Ce²⁺
Answers
Answered by
24
hi friend.....
the correct option is (c) Yb²⁺
Lanthanoid ion with no unpaired electron is diamagnetic in nature.
Ce58 = [Xe]4f² 5d0 6s²
Ce2+ = [Xe]4f² (two unpaired electrons)
Sm62 = [Xe]4f6 5d0 6s2
Sm2+=[Xe]4f6 (six unpaired electrons)
Eu63 = [Xe]4f7 5d0 6s²
Eu2+=[Xe]4f7 (seven unpaired electrons)
Yb70 = [Xe]4f¹⁴ 5d0 6s²
Yb2+=[Xe]4f¹⁴ (no unpaired electrons)
Because of the absence of unpaired
electrons, Yb²⁺ diamagnetic.
hope I answered your question...
the correct option is (c) Yb²⁺
Lanthanoid ion with no unpaired electron is diamagnetic in nature.
Ce58 = [Xe]4f² 5d0 6s²
Ce2+ = [Xe]4f² (two unpaired electrons)
Sm62 = [Xe]4f6 5d0 6s2
Sm2+=[Xe]4f6 (six unpaired electrons)
Eu63 = [Xe]4f7 5d0 6s²
Eu2+=[Xe]4f7 (seven unpaired electrons)
Yb70 = [Xe]4f¹⁴ 5d0 6s²
Yb2+=[Xe]4f¹⁴ (no unpaired electrons)
Because of the absence of unpaired
electrons, Yb²⁺ diamagnetic.
hope I answered your question...
Answered by
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option C is correct
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