Question

Which of the following leads to third line of Balmer spectrum from red end
(A) 2 → 5
(B) 5 → 2
(C) 3→2
(D) 4 → 1​

Answer 1

Explanation:

The transition 5⟶2 leads to third line of Balmer spectrum from red end (for hydrogen atom).

The transition 4⟶2 leads to second line of Balmer spectrum from red end (for hydrogen atom).

The transition 3⟶2 leads to first line of Balmer spectrum from red end (for hydrogen atom).

Balmer series corresponds to transitions to n=2 level.  The spectral lines belongs to visible region.

Answer 2

Answer:

Hope it will help you

Explanation:

In the atomic emission spectra of the hydrogen atom, the emission lines from an excited state nth

 Bohr orbit (n>2) to second Bohr orbit (n=2) is called Balmer series. Thus emission from n>2 to n=2 constitutes the various spectral lines of the Balmer series.

For the third line of Balmer series the transition should take place from n=2+3=5 to n=2 Bohr orbit i.e. from fifth Bohr orbit to second Bohr orbit.