Question

which of the following liberties O_2

upon hydrolysis?
1) Pb_3 O_4
2) KO_2
3) Na_2 O_2
4) Li_2 O_2
​

Answer 1

here we see only Potassium peroxide gives oxygen. therefore the correct option is (b) KO₂

which of the following librates O₂ upon hydrolysis ?

1. Pb₃O₄
2. KO₂
3. Na₂O₂
4. Li₂O₂

solution : hydrolysis means, a molecule of water is added to the chemical substances. in short, hydrolysis means reaction with water of a chemical compound.

here Pb₃O₄ doesn't react with water. so doesn't happen hydrolysis process.

Pb₃O₄ + H₂O ⇒no chemical reaction

hydrolysis of KO₂ gives potassium hydroxide, peroxide and oxygen.

i.e., 2KO₂ + 2H₂O ⇒2KOH + H₂O₂ + O₂

hydrolysis of Na₂O₂ gives sodium hydroxide and peroxide. i.e., Na₂O₂ + 2H₂O ⇒2NaOH + H₂O₂

similarly Hydrolysis of Li₂O₂ gives lithium hydroxide and peroxide. Li₂O₂ + 2H₂O ⇒2LiOH + H₂O₂

here we see only Potassium peroxide gives oxygen. therefore the correct option is (b) KO₂