which of the following list of number form a.p.s? if they form an ap find the common difference D and also write its next three term.
1. 3,3+root 2, 3+2root2, 3+3root 2.....
Answers
Answered by
10
Hope u like my answer
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1).
Yeah it's an A. P. S. which can be determined as, b-a = c - b
Now, to find the common difference (D)
B- A = C - B = D
So, D = 3 + root 2 - 3 = root 2.
So common difference (D) =

It's next three terms will be,

_-_-_-_-_-_-_-_-_-_-_-_-_-_
Hope this is ur required answer
Proud to help you
=====================
1).
Yeah it's an A. P. S. which can be determined as, b-a = c - b
Now, to find the common difference (D)
B- A = C - B = D
So, D = 3 + root 2 - 3 = root 2.
So common difference (D) =
It's next three terms will be,
_-_-_-_-_-_-_-_-_-_-_-_-_-_
Hope this is ur required answer
Proud to help you
Swarup1998:
Nice one! :clap:
Answered by
17
◢GIVEN SERIES :-

______________________________
● WE KNOW THAT
● COMMEN DIFFERENCE = D
◢AND
D = [(n+1)th term - (n)th term.] ____[n≠0]
_____________________________
◢THEN
● WE TAKE "n=1"
◢SO
=> D = [2nd term - 1st term]

____________________[◢ANSWER ]
____________________________
◢NOW
● NEXT THREE TURM OF AP ARE

__________________[◢ANSWER ]
====================================
☆
☆
______________________________
● WE KNOW THAT
● COMMEN DIFFERENCE = D
◢AND
D = [(n+1)th term - (n)th term.] ____[n≠0]
_____________________________
◢THEN
● WE TAKE "n=1"
◢SO
=> D = [2nd term - 1st term]
____________________[◢ANSWER ]
____________________________
◢NOW
● NEXT THREE TURM OF AP ARE
__________________[◢ANSWER ]
====================================
☆
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