Question

which of the following metal ions have maximum number of unpaired electrons 1.Fe+2 2.Co+2 3.Ni+2 4.Mn+2​

Answer 1

Answer:

4) Mn+2 ( 3 unpaired electrons )

• Explanation: 1) Fe+2 : 2 unpaired electrons
• 2) Co+2 : 1 unpaired electrons
• 3) Ni+2 : O unpaired electrons

Answer 2

$Fe^{2+}$ and $Co^{2+}$ are the given metal ions which have maximum number of unpaired electrons.

Explanation:

• Atomic number of iron (Fe) is 26 and in ground state its electronic configuration is $[Ar] 3d^{6} 4s^{2}$.

$Fe^{2+}$ : $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{6}$

There are 4 unpaired electrons present in $Fe^{+}$.

• Atomic number of cobalt (Co) is 27 and in ground state its electronic configuration is $[Ar] 3d^{7} 4s^{2}$.

$Co^{2+}$ : $1s^{2}2s^{2}2p^{6}3s^{2}3p^{7}3d^{6}$

There are 4 unpaired electrons present in $Co^{2+}$.

• Atomic number of nickel (Ni) is 28 and in ground state its electronic configuration is $[Ar] 3d^{8} 4s^{2}$.

$Ni^{2+}$ : $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{8}$

There are 2 unpaired electrons present in $Ni^{2+}$.

• Atomic number of manganese (Mn) is 25 and in ground state its electronic configuration is $[Ar] 3d^{5} 4s^{2}$.

$Mn^{2+}$ : $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{5}$

There are 0 unpaired electrons present in $Mn^{2+}$.

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