Chemistry, asked by wajahatahmed707, 7 months ago

Which of the following molecule DOES NOT show geometrical isomerism? A). n-Hexene B). 2-Butene C). 3-methyl-2-hexene D). 3-Hexene

Answers

Answered by Anonymous
6

Answer:

Hi mate,

Here is the answer,

Answer:-

  • Option C). 3 - methyl - 2 - hexane
  • This does not shoelws geometrical isomerism.

HOPE IT HELPS

Answered by roshnirajeevsl
0

Answer:

n-hexene do not show geometrical isomerism.

Explanation:

Alkenes exhibit geometrical isomerism due to the possibility of different geometrical arrangements in space, as the rotation around the double bond is restricted. Thus, alkenes having the general formula YXC=CXY, XYC=CXZ or XYC=CZW generally exist in the following geometrical arrangements.

(i)cis form: If the identical atoms or groups lie on the same side of the double bond, the isomer is called a cis isomer.

(ii)trans-form: If the identical groups or atoms lie on the opposite side of the double bond, the isomer is a trans isomer.

For exhibiting cis-trans isomerism, the molecule should fulfil the following conditions.

  • It must have at least one double bond.
  • The groups attached to each double-bonded carbon atom must be different.
  • At least one same group is present on the two double-bonded carbon.

n-hexene do not exhibit geometrical isomerism. It possesses the same group on one carbon i.e two hydrogen atoms on one carbon atom.

All other given molecules can exhibit geometrical isomerism.

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