Question

Which of the following molecule has highest percentage of oxygen by mass? [NCERT Pg. 18] (1) H_{2}*O; (3) * C * a * C * O_{3} (2) C*O_{2} (4) C_{2}*H_{5} * O * H​

Answer 1

Answer:

Here's yours answer

Explanation:

Molecular weight of C5​H10​O5​ is 150 grams. [(12∗5) + (1∗10) + (16∗5)]

150 grams of C5​H10​O5​ contain (16∗5) that is 80 grams of Oxygen

Thus, mass percentage of oxygen is 15080​ ∗ 100 that is equal to 53.3%

By using the same formula, we find that, in molecule A, B, and D, mass percentages of Oxygen are  50.7%, 29% and 47.5% respectively.

Thus, C5​H10​O5​ contains the greatest percentage of Oxygen by mass.

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Answer 2

Option 1 is the correct answer. $H_{2}O$ has the highest percentage of oxygen mass.

• The Percentage of Oxygen can be found using the formula,

=> Percentage of Oxygen in a compound = (Weight of Oxygen in the compound) x 100/ (Total weight of the Compound).

• Percentage of Oxygen in H$_{2}$O = (Weight of Oxygen in H2O x 100)/(Weight of H2O)

=> Percentage of Oxygen in H$_{2}$O = (16 x 100)/18,

=> Percentage of Oxygen in H$_{2}$O = 88.889%.

• Percentage of Oxygen in CaCO$_{3}$ = (Weight of Oxygen in CaCO$_{3}$ x 100)/(Weight of CaCO$_{3}$)

=> Percentage of Oxygen in CaCO$_{3}$ = (48 x 100)/100,

=> Percentage of Oxygen in CaCO$_{3}$= 48%.

• Percentage of Oxygen in CO$_{2}$ = (Weight of Oxygen in CO$_{2}$ x 100)/(Weight of CO$_{2}$)

=> Percentage of Oxygen in CO$_{2}$ = (32 x 100)/44,

=> Percentage of Oxygen in CO$_{2}$ = 72.72%.

• Percentage of Oxygen in C$_{2}$H$_{5}$OH = (Weight of Oxygen in C$_{2}$H$_{5}$OH x 100)/(Weight of C$_{2}$H$_{5}$OH)

=> Percentage of Oxygen in CO$_{2}$ = (16 x 100)/46,

=> Percentage of Oxygen in CO$_{2}$ = 34.78%.

Therefore, the highest percentage of oxygen by mass from the mentioned options is H20 (Water). Hence, Option 1 is the correct answer.