Math, asked by sveer5843, 1 month ago

which of the following number are not perfect cubes ? (a) 7803​

Answers

Answered by musabiqbal10
0

Answer:

It is evident that the prime factors of 7803 cannot be grouped into triples of equal factors such that no factor is left over. Therefore, 7803 is a not perfect cube. ... Thus, 7803 should be divided by 289 to make it a perfect cube.

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