Question

which of the following number can't be the area of a square with integeral value side? a)3481 b) 2116 c)3114 d) 3136 . . give answer with explanation and solve it :)​

Answer 1

Step-by-step explanation:

$\sqrt{3481} = 59$

$\sqrt{2116} = 46$

$\sqrt{3114} = 55.803$

$\sqrt{3136} = 56$

3114 is not the square of any number

Answer 2

$\huge {\mathfrak {\green {Answer \:is: Option\: C}}}$

$\huge {\mathfrak {\pink {Explanation:}}}$

$\large {\boxed {\orange {\mathfrak {For \: a}}}}$

Let the area of a square be 3481 (imagine)

Area of a square = (side)²

Therefore, ATQ

(side)² = 3481

=⟩ side = √(3481)

= 59

Hence, the area of a square can be 3481 (square possible)

$\large {\boxed {\orange {\mathfrak {For \: b}}}}$

Let the area of a square be 2116 (imagine)

Area of a square = (side)²

Therefore, ATQ

(side)² = 2116

=⟩ side = √(2116)

= 46

Hence, the area of a square can be 2116 (square possible)

$\large {\boxed {\orange {\mathfrak {For \: c}}}}$

Let the area of a square be 3114 (imagine)

Area of a square = (side)²

Therefore, ATQ

(side)² = 3114

=⟩ side = √(3114)

= 55.80...

Hence, the area of a square cannot be 3114 (square impossible)

$\large {\boxed {\orange {\mathfrak {For \: d}}}}$

Let the area of a square be 3136 (imagine)

Area of a square = (side)²

Therefore, ATQ

(side)² = 3136

=⟩ side = √(3136)

= 56

Hence, the area of a square can be 3136 (square possible)