Question

which of the following number is an irrational number
${a} \: \: \sqrt{6} - 4$
$b \: (3 - \sqrt{3} ) \: (3 + \sqrt{3} )$
$c \: \: \sqrt{5 } + 3$
$d \: \: - \sqrt{25}$




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Answer 1

Answer:

${a} \: \: \sqrt{6} - 4$ = Irrational

$b \: (3 - \sqrt{3} ) \: (3 + \sqrt{3} )$= (3)² - (√3)² = 9 - 3 = 6 [ Rational]

$c \: \: \sqrt{5 } + 3$ = Irrational

$d \: \: - \sqrt{25}$ = -5. [ Rational]

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