Math, asked by somaiahsouthkar, 3 months ago

Which of the following numbers are divisible by 2, by 3 and by 6?
(i) 321729 (ii) 197232 (iii) 972132 (iv) 1790184
(v) 312792
(vi) 800552
(vii) 4335 (viii) 726352​

Answers

Answered by Anonymous
8

Answer:

Radhe Radhe

(i) it is divisible by 3

(ii)it is divisible by 2

(iii)it is divisible by 2

(iv) it is divisible by 2

(v) it is divisible by 2

(vi) it is divisible by 6

(vii) it is divisible by 2

some are 2 and 6 both

Answered by kamaleshkumarc2007
7

Answer:

Divisible by 3 - To add all the digits and find whether it is divisible by 3

Divisible by 2 - To check last digit whether divisible by 2

Divisible by 6 - To check whether it is divisible by both 2 and 3

Step-by-step explanation:

(i) 3 + 2 + 1 + 7 + 2 + 9 = 24

   Divisible by 3

(ii) 1 + 9 + 7 + 2 + 3 + 2 = 24

    Divisible by 3

    Divisible by 2

    Divisible by 6

(iii) 9 + 7 + 2 + 1 + 3 + 2 = 24

     Divisible by 3

     Divisible by 2

     Divisible by 6

(iv) 1 + 7 + 9 + 0 + 1 + 8 + 4 = 30

    Divisible by 2

(v) 3 + 1 + 2 + 7 + 9 + 2 = 24

    Divisible by 3

    Divisible by 2

    Divisible by 6

(vi) 8 + 0 + 0 + 5 + 5 + 2 = 20

    Divisible by 2

(vii) 4 + 3 + 3 + 5

    Divisible by 3

(viii) 7 + 2 + 6 + 3 + 5 + 2 = 25

     Divisible by 2

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