Question

Which of the following numbers are divisible by 2, by 3 and by 6?
(i) 321729 (ii) 197232 (iii) 972132 (iv) 1790184
(v) 312792 (vi) 800552 (vii) 4335 (viii) 726352​

Answer 1

Answer:

III point, IV point, V point, VI point, VII point,

Step-by-step explanation:

first of all we will look to the last word of no. like the no. 321729 the last digit no. is 9 so 9 is not divisible by 2 but by 3 so it cannot be divisible by all of three { 6 is also not divisible by this no. becz the no which is divisible by 2 and 3 is also divisible by 6}

NOW, look on II point

197232 is no.

it can be divisible by 2 becz last no. is 2

but cannot divisible by 3 becz when we add 1+9+7+2+3+2 = 25 which is not divisible by 3 and same not by 6 { the reason is simple this no. cannot be divisible by 3 so cannot divisible by 6 }

THE SAME FORMULA WILL APPLY TO ALL OF THE NO.